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General transcription factors in eukaryotes

01 / 10 / 2021 Assignment

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Question 1
Question 2
Question 3
Question 4
What is the function of general transcription factors in eukaryotes?
Selected Answer: D. They bind to regulatory promoters to increase the rate of transcription.
Answers: A. They direct nucleosome assembly.
B. They are a part of the basal transcription apparatus.
C. They are DNA sequences to which RNA polymerase binds.
D. They bind to regulatory promoters to increase the rate of transcription.
E. They bind to enhancers to allow minimal levels of transcription.
In prokaryotes, rho-independent transcription termination depends on a secondary structure
formed in
Selected Answer: E. the RNA polymerase that is transcribing the gene.
Answers: A. a protein factor that binds to RNA polymerase.
B. a protein factor that binds to the RNA that is being transcribed.
C. the RNA that is being transcribed.
D. the DNA template.
E. the RNA polymerase that is transcribing the gene.
If the following DNA strand were used as a template, what would the sequence of an RNA be?
5′ GTACCGTC 3′
Selected Answer: A. 5′ CAUGGCAG 3′
Answers: A. 5′ CAUGGCAG 3′
B. 5′ GUCGGUAC 3′
C. 5′ GACGGUAC 3′
D. 5′ GUACCGUC 3′
E. 5′ GACGGTAC 3′
Which statement about RNA polymerase is NOT true?
Selected
Answer:
E.
During transcription of a gene, RNA polymerase reads only one strand of
DNA.
Answers: A. RNA polymerase binds to a promoter to initiate transcription.
B. RNA polymerase reads a template strand of DNA 5′ to 3′.
C.
RNA polymerase adds a ribonucleotide to the 3′ end of a growing RNA
molecule.
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Question 5
Question 6
Question 7
D. RNA polymerase has many subunits.
E.
During transcription of a gene, RNA polymerase reads only one strand of
DNA.
The TATA-binding protein (TBP) binds to the TATA box sequence in eukaryotic promoters. What is
its function in transcriptional initiation?
Selected
Answer:
A.
It binds to the promoter and positions the RNA polymerase correctly at the start
site
Answers: A.
It binds to the promoter and positions the RNA polymerase correctly at the start
site
B.
It blocks access of RNA polymerase to the promoter, until removed by general
transcription factors.
C.
It is the subunit of prokaryotic RNA polymerase that is required to recognize
promoters.
D.
It modifies histones so that nucleosomes can be removed from DNA for
transcription.
E. It creates a phosphodiester bond between the nucleotides.
What type of synthesis occurs on the leading strand?
Selected Answer: E. Discontinuous
Answers: A. Dispersive
B. Recombination
C. Conservative
D. Continuous
E. Discontinuous
All DNA polymerases synthesize new DNA by adding nucleotides to the _____ of the growing DNA
chain.
Selected Answer: B. 3′ OH
Answers: A. 5′ OH
B. 3′ OH
C. 5′ phosphate
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Question 8
Question 9
Question 10
D. nitrogenous base
E. 3′ phosphate
DNA polymerases require all of the following for DNA replication, EXCEPT
Selected Answer: B. 3′ to 5′ polymerase activity.
Answers: A. dNTPs.
B. 3′ to 5′ polymerase activity.
C. DNA template.
D. primer.
E. free 3′ OH.
Suppose Meselson and Stahl had obtained the following results in their experiment. These results
would be consistent with which model of replication?
Selected Answer: D. Semiconservative and conservative replication
Answers: A. Dispersive replication only
B. Conservative replication only
C. Semiconservative replication only
D. Semiconservative and conservative replication
E. Semiconservative and dispersive replication
siRNAs and miRNAs function in which of the following processes?
Selected Answer: A. Transcription
Answers: A. Transcription
B. Translation
C. RNA interference
D. RNA splicing
E. RNA editing
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Question 11
Question 12
Question 13
Question 14
Telomerase activity is most likely to be found in which cells in humans?
Selected Answer: D. Germ line
Answers: A. Red blood cells
B. Muscle cells
C. Neurons
D. Germ line
E. Any type of somatic cell
The list of events below describes eukaryotic pre-mRNA processing. Please select the choice that
lists the events in correct sequential order.
1. Recognition and binding the 3′ AAUAAA sequence by specific protein factors
2. Cleavage at the poly(A) site
3. Addition of the 5′ cap
4. Export to the cytoplasm
5. Addition of the poly(A) tail
Selected Answer: D. 3, 1, 2, 5, 4
Answers: A. 4, 2, 3, 1, 5
B. 2, 3, 4, 5, 1
C. 5, 4, 1, 3, 2
D. 3, 1, 2, 5, 4
E. 1, 3, 5, 4, 1
Which of the following elements would not be found on an mRNA molecule?
Selected Answer: A. 3′ untranslated region
Answers: A. 3′ untranslated region
B. 5′ untranslated region
C. Promoter
D. Protein-coding region
E. Start and stop codons
Scientists once believed that each gene can encode a single polypeptide. We now know that
__________ and ___________ allow a single gene to encode more than one polypeptide.
Selected Answer: E. alternative processing; RNA editing
Answers: A. gene silencing; RNA interference
B. DNA methylation; chromatin condensation
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Question 15 0 out of 1 points
How many introns are present on a gene that consists of 4 exons?
Selected
Answer:
E.
The number cannot be determined from the information
provided.
Answers: A. 2
B. 3
C. 4
D. 5
E. The number cannot be determined from the information



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