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# State the null and alternative hypotheses for the test. (b) Calculate the test statistics. (c)Determine the rejection region(s) for the test. (d) State the conclusion for the test giving reasons for your answer.

The Agriculture Department
of a certain country reported that the average coffee consumption in the
country, in 2014, was 26.0 gallons per person. A recently taken random sample
of 400 residents of the country found a mean coffee consumption of 26.7 gallons
with a sample standard deviation of 6.8 gallons. Assuming that the population
of coffee consumption is normally distributed, test, at the 10% level of
significance, whether the mean coffee consumption is different from the
reported 26.0 gallons, by answering the following:

(a)State the
null and alternative hypotheses for the test.

(b) Calculate
the test statistics.

(c)Determine
the rejection region(s) for the test.

(d) State the

Question 2[10 marks]

Six months after graduating from college,
randomly selected graduates were surveyed to determine their level of job
pressure. The data was inputted into MINITAB Version 17.0 for analysis to
determine whether level of job pressure is independent of gender. The following
output, Exhibit 1, was generated using MINTAB:

Chi-Square
Test for Association: Age (years), Degree of Job Pressure

 Rows: Age (Years) Columns: Degree of Job Pressure Low Medium High All Less than 20 22 18 24 64 20.84 21.58 * 0.06424 0.59346 0.27173 20 – 39 52 48 46 146 47.55 49.23 49.23 0.41687 0.03054 ** 40 – 59 60 65 61 186 60.57 62.71 62.71 0.00545 0.08343 0.04677 60 and Above 36 45 45 126 41.03 42.48 42.48 0.61768 0.14915 0.14915 All 170 176 176 522 Cell Contents: Count Expected count Contribution to Chi-square

Chi-Square = 2.640, DF = ***, P-Value
= 0.852

(a)State the
null and alternative hypotheses for the test.

(b) Determine
the missing values “*”, “**” and “***”.

(c)State the